| Students
know genetic information passed from parents to offspring is coded
in the DNA molecule. E/S
During the first half of the 20th century a debate
among biologists centered around whether proteins or deoxyribonucleic
acid (DNA) was the molecule of inheritance. In 1928, Fredrick Griffith
first proposed that the transfer of DNA between bacteria caused transformation,
but could not provide convincing proof. In the 1940s Oswald Avery
and others were able to devise experiments that provided the evidence
that Griffith lacked. However it took an experiment by Alfred Hershey
and Martha Chase in 1952 to finally demonstrate to the scientific
community that DNA and not proteins was the molecule of inheritance.
Today we know that the coded message for our traits is based in the
four nucleotides of DNA. These four bases adenine (A), thymine (T),
guanine (G), and cytosine (C) are divided into two groups called purines
(A & G) and pyrimidines (T & C). The Human Genome Project
has confirmed that the DNA in a typical human cell contains over 3
billion base pairs (bp). In these 3 billion bp are 20,000 to 25,000
genes that code for proteins, which in turn code for our traits. Each
gene is a specific sequence of nucleotides located on one of the DNA
strands.
The DNA in the human body is spread over 24 distinct chromosomes
which range in size from 50 million to 250 million bp.
To learn more about the findings of the Human Genome Project go to
http://www.ornl.gov/sci/techresources/Human_Genome/home.shtml
DNA is a nucleic acid that contains nucleotides running in two strands
and twisted into a double helix. Each nucleotide contains three molecules
(a base, a deoxyribose sugar and a phosphate group). The nucleotides
pairings are shown in the illustration below. These pairings also
referred as complementary base pairs.
In the illustration above you will see that the base adenine is
paired with the base thymine and the base guanine is paired with the
base cytosine. The idea of these pairing was first discovered by Edwin
Chargaff in the late 1940’s. In working with cells from different
organisms Chargaff discovered that the percentages of adenine in a
cell were equal to the percentages of thymine, and the percentages
of guanine were equal to the percentages of cytosine in the nucleus.
These pairing have become known as “Chargaff’s Rule”.
However the meaning of this discovery was not clear until Watson and
Crick developed their mode of DNA in 1953.
The genetic code in DNA is passed along via mitosis, meiosis or binary
fission. Prior to these processes the molecules of DNA in the parent
cell must be copied via DNA replication. In their 1953 paper Watson
and Crick proposed that each strand of the DNA molecule makes a complementary
copy of itself through DNA replication prior to cell division. In
1957, Meselson and Stahl devised an experiment that demonstrated this
semi-conservation nature of DNA replication as first proposed by Watson
and Crick. In this process each strand from the original DNA molecule
gets a new complementary strand. Thus each new DNA molecule has 1
(one) strand from the “old” molecule and one “new”
strand that is an exact copy of the original.
To learn more about the history of DNA’s discovery go to
http://www.dnai.org/
Before the genetic code is passed from parents to offspring via
meiosis or from one cell to another new cell via mitosis the DNA must
be replicated. As illustrated in Figure 2 each strand of the DNA makes
a complementary copy of itself.
In a simplified view the copying can be seen in Figure 3. The DNA
“unzips” and complementary bases are brought to each strand
and the new stands “rezip” forming two identical copies
of the original DNA molecule.
Biologists have discovered that the actual process is far more complicated.
First a molecule called helicase unwinds the DNA double helix. Before
DNA polymerase travels along each strand matching complementary bases,
a short sequence of RNA nucleotides is matched with the separated
strands by RNA primase. The copying of each strand, however, is different.
One strand called the leading strand is copied in a continuous fashion,
while the other called the lagging strand is copied in fragments called
Okazaski fragments as seen in the illustration below. Later DNA ligase
will join these fragments.
The rate at which new nucleotides are added is about 50 per second
and would take 53 days to replicate the largest human chromosome if
replication began at one end and proceeded to the other end. As such
the replication of any chromosome begins at many origins along the
chromosome. In fruit fly chromosomes there are some 3500 origin sites
where DNA replication begins simultaneously.
To learn more and to view an animation of DNA replication go to
http://www.johnkyrk.com/DNAreplication.html
and, http://www.stolaf.edu/people/giannini/flashanimat/molgenetics/dna-rna2.swf
and, http://www.emc.maricopa.edu/faculty/farabee/biobk/BioBookDNAMOLGEN.html
The later is a part of the online textbook “Online Biology
Book”. Numerous diagrams are included along with a description
of DNA structure and replication. Links are also provided to other
websites.
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Performance
Benchmark L.12.A.1
Students know genetic information passed from parents to offspring
is coded in the DNA molecule. E/S
Common misconceptions associated with this benchmark:
1. Students incorrectly assume that DNA is vastly different
amongst members of the same species.
Despite the fact that humans contain over 3 billion bp in their DNA,
researchers have found that most of DNA is quite similar. Based on
sequencing to date it appears that on average two unrelated people
have one different nucleotide per 1000 bases. Thus with 3 billion
bp total bases this means there are 3 million differences between
individuals or less than 0.01% difference between individuals. These
differences are called single nucleotide polymorphisms or SNPs (pronounced
“snips”)
Aside from the fact each human has a unique combination of genes;
these genes are shared by all members of the human species. The goal
of the Human Genome Project is to identify these genes and than determine
what each gene codes for in humans.
To learn more about SNPs go to
http://www.ornl.gov/sci/techresources/Human_Genome/faq/snps.shtml
2. Students mistakenly assume that DNA coding for molecules
is different between different species.
While a species has a unique gene pool that defines that species,
many genes are shared by humans and other organisms. For example 45%
of the genes found in fruit flies are also found in humans and we
share approximately 96% of our genes with chimpanzees. This should
not be surprising considering the number of biochemical pathways that
are commonly found in organisms. For example most organisms obtain
energy or ATP by cellular respiration and the enzymes (coded for by
DNA) involved in this biochemical pathway are found in most organisms.
To learn more about the similarity of human and chimpanzee DNA go
to
http://news.nationalgeographic.com/news/2005/08/0831_050831_chimp_genes.html
3. Students incorrectly assume that mutations in DNA
are always harmful.
Single base errors in DNA copying are called point mutations, however,
these are rare. During DNA replication the error rate is 1 in 10,000
bases being copied. Most of these errors are corrected by DNA proof
readers. Secondly if an error is not corrected, because of the redundancy
of the genetic code the same amino acid may be coded for by the codon.
This is called a silent mutation. Or an amino acid with similar properties
can be coded for by the “mutant” codon which is sometimes
called a neutral mutation. Note the table below.
At the same time some point mutations can be harmful. In the table
below the DNA triplet and mRNA codon are shown for the 6th amino acid
for normal hemoglobin. In sickle-cell anemia a mutation from T to
A leads to the replacing of glutamic acid with valine. The result
is an abnormally shaped hemoglobin molecule during low oxygen concentration
in the blood. And if the first C is replace by A, the result is the
termination of protein synthesis and no hemoglobin molecule is produced.
| DNA Triplet |
mRNA codon |
Amino Acid |
Properties |
Mutation Type |
| CTC |
GAG |
Glutamic acid |
Hydrophobic |
Normal codon |
| CTT |
GAA |
Glutamic acid |
Hydrophobic |
Neutral |
| CTA |
GAU |
Aspartic acid |
Hydrophobic |
Silent |
| CAC |
GUG |
Valine |
Hydrophilic |
Missense |
| ATC |
UAG |
Stop |
Termination |
Nonsense |
All humans with blood type O are also carrying a mutation. The genes
for blood type code for proteins found on the red blood cell. Many
inherit the genes for the A and B proteins. However due to a point
mutation in our ancestral past the coding for these proteins was lost,
thus those who inherit the alleles for O lack coding for either protein.
To learn more about DNA mutations go to
http://www.genetichealth.com/G101_Changes_in_DNA.shtml#Anchor2
http://evolution.berkeley.edu/evolibrary/article/0_0_0/mutations_01
4. Students incorrectly assume that DNA and chromosomes
are not the same.
Both of these are names for the same molecule. Humans have 46 chromosomes
and each chromosome contains a specific sequence of DNA nucleotides
which are codes for our genes. However, each chromosome contains a
unique combinations of genes. Genes found in Chromosome #1 are not
the same as those found in chromosome #2..
To learn more about what genes have been discovered on each human
chromosome and to order a free poster showing human genome landmarks
go to
http://www.ornl.gov/sci/techresources/Human_Genome/posters/chromosome/
5. Students inaccurately assume that the amount of
genetic material is equal in males and females.
While each offspring, regardless of sex, receives 23 chromosomes
from each parent, the amount of DNA and the genes they receive is
not equal. Both males and female receive the same 22 pairs of autosomes
(non-sex chromosomes) and therefore each receives equal number of
genes for non-sexual characteristics found on these chromosomes. However
the sex chromosomes (X and Y) do not contain equal number of genes
or types of genes.
The X chromosome represents approximately 5% of the total DNA in
cells and contains approximately 1300 genes. These 1300 genes not
only include genes for femaleness, but genes for such traits as blood
clotting and color vision. On the other hand the Y chromosome contains
approximately 2% of the DNA in a cell or approximately 300 genes which
will be inherited by males only, since females do not inherit a Y
chromosome. Thus males inherit both the X and Y chromosomes, they
will inherit all genes for the same traits as females, but females
will lack any genes found on the Y chromosome.
To learn more about the X and Y chromosomes go to
http://ghr.nlm.nih.gov/ghr/chromosomes
6. Students incorrectly believe that the amount of
DNA varies in organisms based upon their “complexity”
While is true that humans have approximately 1000 times more DNA
than a typical bacterium, the Human Genome Project has reveled some
interesting surprises. Humans have approximately 3.0 X 109 base pairs
(bp) and 20,000 to 25,000 genes. But notice the figures for other
organisms.
| Organism |
DNA base pairs |
Approximate # of Genes |
Chromosome # |
Mutation Type |
| Rice |
3.9 X 109 |
37,000 |
12 |
Normal codon |
| Maize |
2.5 X 109 |
Over 50,000 |
20 |
Neutral |
| Mouse |
2.5 X 109 |
22,500 |
40 |
Silent |
| Whisk fern |
2.5 X 1011 |
? |
? |
Missense |
| Sea urchin |
8.14 X108 |
23,000 |
44 |
Nonsense |
To view more examples, go to
http://users.rcn.com/jkimball.ma.ultranet/BiologyPages/G/GenomeSizes.html#Anopheles
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Performance
Benchmark L.12.A.1
Students know genetic information passed from parents to offspring
is coded in the DNA molecule. E/S
Sample Test Questions
1. In Chargaff’s rule, the base-pairing
rule, state that in DNA
a. the amount of adenine equals the
amount of thymine.
b. the amount of guanine equals the amount of thymine.
c. the amount of cytosine equals the amount of thymine.
d. the amount of adenine equals the amount of guanine
2. Which one of the following nucleotide pair
bonds would be found in a DNA molecule?
a. cytosine-guanine
b. adenine-cytosine
c. cytosine-uracil
d. adenine-guanine
3. The base-pairing rules state that the following
are base pairs in DNA:
a. adenine—thymine; uracil—cytosine.
b. adenine—thymine; guanine—cytosine.
c. adenine—guanine; thymine—cytosine.
d. uracil—thymine; guanine—cytosine.
4. During DNA replication, a complementary strand
of DNA is made for each original DNA strand. Thus, if a portion of
the original strand is CCTAGCT, then the new strand will be
a. TTGCATG
b. CCTAGCT
c. AAGTATC
d. GGATCGA
5. Which statement below correctly describe the
relationship between genome size and organism “complexity”
a. As organisms get more complex their genomes get larger.
b. Organism of similar complexity have genomes of similar size.
c. There appears to be little relationship between complexity and
genome size.
d. Individuals of the same species have vastly different genomes.
Students know genetic information passed from parents
to offspring is coded in the DNA molecule. E/S
Answers to Sample Test Questions
1. (a)
2. (a)
3. (b)
4. (d)
5. (b)
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Performance Benchmark L.12.A.1
Students know genetic information passed from parents to offspring
is coded in the DNA molecule. E/S
Intervention Strategies and Resources
The following is a list of intervention strategies and resources
that will facilitate student understanding of this benchmark.
1. Movie on the discovery of DNA and its
molecular structure
To understand and appreciate the discovery of DNA as the molecule
of inheritance teachers can begin by showing the video Biologix: Development
of Molecular Genetics which last 29 minutes. It is divide into two
parts. The first part talks about the works of Griffith, Avery, and
Hershey/Chase that lead to the establishment of DNA as the molecule
of inheritance. In the second part the work Levene, Chargaff, Franklin
and Watson/Crick is and their efforts to establish the structure of
DNA. This video is useful for all levels of biology.
To find this video, go to the KLVX Video Streaming website at
http://www.klvx.org/
2. The building of the DNA model
One of the important aspects of science is to build model molecular
structures that scientists are trying to understand. In their efforts
to discover the structure of DNA Watson and Crick resorted to a variety
of models. To help students appreciate this aspect of science students
can also build their own models of DNA.
To learn more about building DNA models and for lesson plans go to
http://www.ncbe.reading.ac.uk/DNA50/cutout.html
http://www.ncbe.reading.ac.uk/NCBE/PROTOCOLS/DNA/modelling.html
http://biology.about.com/library/bldnamodels.htm
3. DNA Extraction experiments
Along with model building students can very easily perform DNA extraction
experiments at little cost using household items. The Genetic Science
Learning Center website provides a simple and straight forward protocol
for extracting DNA from wheat germ. In addition it provides information
as to why various items are used in the protocol. For example it explains
the role of detergent in extracting the DNA from the wheat germ. This
site also has a virtual DNA extraction lab.
To review the virtual DNA extraction lab at the Genetics Science
Learning Center, go to
http://www.teachersfirst.com/getsource.cfm?id=5346
4. DNA fingerprinting activity
To understand that our genes are passed from parent to offspring the
teacher could have the students look at the role of DNA fingerprinting
in helping to identify individuals. At this Nova Online site students
can play the role of detective and use genetic fingerprinting to solve
a crime.
To review the DNA fingerprinting lab at Nova Online, go to
http://www.pbs.org/wgbh/nova/sheppard/analyze.html
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